Higher and foundation tier
Separating out mixtures is a task all good chemists need to be able to do well. There are different methods used to separate mixtures, these include: filtration, distillation, chromatography and finally evaportion and crystallisation. The method used depends upon the mixture to be separated. Once you know how each method works then you can decide which one to use.
Insoluble substances such as sand or chalk will not dissolve in water. The sand and chalk particles are too large to fit into the gaps between the water molecules and so are insoluble. It is very easy to separate out an insoluble substance from water (or any other solvent) simply by filtering. The water molecules and any dissolved particles are small enough to pass through the small holes in the filter paper but the sand or chalk molecules are too large to fit through the small holes, so they get trapped in the filter paper. The solid part of any mixture that is trapped in the filter paper is called the residue and the portion that passes through the filter paper is called the filtrate. A simple filtration practical is set out in the image below. Here a mixture of insoluble sand is mixed with salt water.
The filtrate, salt water is a solution of water with salt dissolved in it. How can you separate this solution out into salt and water? We cannot filter, filtering only separates insoluble substances from a liquid (a solvent). The simplest way would simply be to pour the salt solution, the filtrate, into an evaporating basin and leave it on a warm window ledge for a few days. The water (the solvent) will then evaporate and crystals of salt will start to grow. This process of evaporation can be "speeded up" by placing the evaporating basin on a tripod stand and warming gently with a low heat Bunsen burner flame. The water (solvent) will start to evaporate and the remaining solution will slowly become more and more concentrated, eventually when the solvent can dissolve no more salt (solute) then crystals will start to grow and form on the edges of the evaporating basin. Generally the slower the evaporation occurs the more time the crystals have to grow and the larger the crystals become. The image below shows how this could be done.