testing for anions

Chemistry only

You need to learn how to test for carbonate ions (CO32-), halide ions (Cl-, Br-, I-) and sulfate ions (SO42-).

Testing for carbonate ions (CO32-)

test for carbonate ions The caronbate ion, CO32- will react with a dilute acid to release carbon dioxide gas. Limewater is used to test for carbon dioxide, it turns milky or chalky when CO2 is bubbled through it. The set-up is shown opposite, approximately 10ml of dilute hydrochloric acid is added to a few granules of the suspected metal carbonate. If carbonate ions are present then CO2 gas will be released, this will bubble through the limewater and turn it milky/chalky, e.g if the carbonate is calcium carbonate then the following reaction will occur:

calcium carbonate(s) + hydrochloric acid(aq) → calcium chloride(aq) + carbon dioxide(g) + water(l)
CaCO3(s) + 2HCl(g) → CaCl2(aq) + CO2(g) + H2O(l)



Test for sulfate ions (SO4)

If a solution contains sulfate ions and a few drops of barium chloride solution are added an insoluble white precipitate of barium sulfate will form. However if the solution also contains carbonate ions then a white precipiate of barium carbonate will also form. So it might seem that this is not really a very good test for sulfate ions as it also gives a positive test for carbonate ions, but if a few drops of hydrochloric acid are added then any carbonate present will react with the acid to release carbon dioxide gas, as in the above test for carbonate. However no fizzing is seen if only the sulfate ion is present. An outline of the test is shown below:

test for sulfate ions

Testing for the halide ions, chloride, bromide and iodide ions.

Halide ions are chloride, bromide and iodide ions. Most compounds containing the chloride, bromide and iodide ions that you will meet are likely to be soluble, but silver chloride, bromide and iodide are insoluble and have different colours. Silver chloride is white, silver bromide is cream and silver iodide is yellow. To test for the presence of Cl-, Br- and I- ions in solution simply add a few drops of nitric acid and then add a few drops of the silver nitrate solution. If the halides are present then a solid insoluble precipitate will be produced. This is summarised in the diagram below.

test for halide ions

The equations below may help you to understand these reactions in a little more detail.

sodium chloride(aq) + silver nitrate(aq) → silver chloride(s) + sodium nitrate dioxide(aq)
NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)
and with bromide ions:
sodium bromide(aq) + silver nitrate(aq) → silver bromide(s) + sodium nitrate dioxide(aq)
NaCl(aq) + AgNO3(aq) → AgBr(s) + NaNO3(aq)
and with iodide ions
sodium iodide(aq) + silver nitrate(aq) → silver iodide(s) + sodium nitrate dioxide(aq)
NaI(aq) + AgNO3(aq) → AgI(s) + NaNO3(aq)

Key Points

Practice questions

Check your understanding - Questions on tests for anions

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