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Higher and foundation tiers

Balancing equations

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If you think about what happens to the particles during a chemical reaction you would probably realise that all the particles present in the reactants appear in the products. All that really happens during a chemical reaction is that the particles rearrange themselves as they change from reactants into products. This idea is really quite simple but crucial in understanding what happens during chemical reactions. The law of conservation of mass states that the total mass of the reactants must be equal to the total mass of the products; nothing appears or disappears during chemical reactions. All the particles that you start with you end up; they will probably be in a different form but they are all still there!

Balancing equations

When we balance symbolic equations all we are doing really is simply counting atoms, to make sure that all the atoms are accounted for and none are lost or have gone missing. Technically it's not atoms that we are counting it's the number of moles of reactants and products in the chemical reaction; but then again moles are just a way of counting large numbers of atoms. The only way to master the skill of balancing equations is to practice it. Luckily there are few simple rules which can make it easier for us.

Working out chemical formulae is another useful skill which is easy to master and will improve your confidence in your chemistry work. However on this page do not worry about any of the formulae for any of the reactants or products just concentrate on balancing the equations; if you would like more help on working out formula then simply click here.

Worked examples

Below are some worked examples on how to balance chemical equations. Go through the worked examples and then try to balance equations yourself by completing the practice questions. The only way to get good at balancing equations is to balance lots of them, it's often trial and error until you get more confident at balancing equations.

Example 1.

Magnesium ribbon burns in air with a brilliant white flash to form magnesium oxide. We can represent this reaction with word and symbolic equations as shown below:
Word equation:
magnesium + oxygenmagnesium oxide

Symbolic equation:
Hint: Remember that oxygen gas is a diatomic gas, its goes around in pairs!
Mg + O2 MgO

Model equation: Model or ball and stick model for the formation of magnesium oxide Now if you look carefully at the symbolic and the model equations you will see that they are not balanced. On the reactants side of the equation there is 1 atom/mole of magnesium and 2 atoms/moles of oxygen. On the products side of the equation there is 1 atom/mole of magnesium and 1 atom/mole of oxygen. We are missing 1 atom/mole of oxygen on the products side of the equation. Now the simple but incorrect way to fix this is simply to change the formula for magnesium oxide as shown below:
Mg + O2MgO2
However MgO2 is not the correct formula for magnesium oxide!
To balance equations the first rule is simple - DO NOT change any of the formula for the compounds you are given. You balance equations by putting numbers in front of each of the reactants and products formulae until the number of atoms on each side of the equation balances.

Ball and stick or model equation for the formation of magnesium oxide

By inserting "2" into the equation above there are now equal numbers of atoms of each element on the reactants and products side of the equation.

Example 2.

Hydrogen burns in air to form hydrogen oxide or water. We can represent this reaction with word and symbolic equations:
Word equation:
hydrogen + oxygenhydrogen oxide

Symbolic equation:
H2 + O2 H2O
Model equation: Space filled model equation to show the formation of water As in example 1 this equation is not balanced. There are 2 atoms of oxygen present on the reactants side of the equation and only 1 atom on the product side. So remember to balance the equation you can only put numbers in the front of each substance, you cannot change any of the formula given. Space filled model and balanced symbolic equation to show the formation of water. By inserting "2" into the equation above we now have 4 hydrogen atoms on the reactants side and 4 on the products side of the equation. There are 2 oxygen atoms on each side of the equation so it is balanced.

Example 3.

Methane is the gas used in Bunsen burners; it burns to form carbon dioxide and water vapour. We can represent this reaction with word and symbolic equations:
Word equation:
methane + oxygen carbon dioxide + hydrogen oxide

Symbolic equation:
CH4 + O2 CO2 + H2O
This equation is not balanced; there are not enough hydrogen atoms on the products side of the equation and too many oxygen atoms on the products side of the equation. To make balancing equations which contain hydrogen and oxygen as well as other elements easier to balance as a general rule balance the oxygen atoms last; the hydrogen atoms second last and any other elements first.
This equation can be balanced by:
CH4 + O2 CO2 + 2H2O

Finally check the number of atoms of oxygen atoms present on each side of the equation. Here there are 2 atoms of oxygen present on the reactant side of the equation but there are 4 atoms of oxygen on the products side of the equation, so to balance the oxygen atoms insert a "2" in front of the oxygen in the reactants side of the equation:

CH4 + 2O2 CO2 + 2H2O

The equation is now balanced.

Space filled models and balanced symbolic equation to show the combustion of methane gas. It is worth mentioning that really the only way to master balancing equations is to have a go yourself. So please click the link below for the practice questions. You should also be aware that in the examples above we were trying to balance the number of atoms of each element in the equations, however strictly speaking we should be talking about balancing the number of moles of each substance present.

Key points

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